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  Filtrage type relations : +   - (ex: 4, 12, 18, 36, 444, 555, 777)
  Filtrage valeur :          min   max
  Filtrage type noeuds :   +   - (ex: 4, 6, 8, 9, 10, 12, 18, 36, 444, 555, 777)

  Présentation de sortie :   (ex: -rien-, cloud, nicecloud)
 

'South Staffordshire'
(id=4074732 ; fe=South Staffordshire ; type=1 ; niveau=200 ; luminosité=25 ; somme entrante=1289 creation date=2016-12-28 touchdate=2025-08-30 10:54:51.000)
≈ 11 relations sortantes

  1. South Staffordshire -- r_associated #0: 59 / 1 -> Staffordshire
    n1=South Staffordshire | n2=Staffordshire | rel=r_associated | relid=0 | w=59
  2. South Staffordshire -- r_associated #0: 58 / 0.983 -> South
    n1=South Staffordshire | n2=South | rel=r_associated | relid=0 | w=58
  3. South Staffordshire -- r_associated #0: 28 / 0.475 -> Midlands de l'Ouest
    n1=South Staffordshire | n2=Midlands de l'Ouest | rel=r_associated | relid=0 | w=28
  4. South Staffordshire -- r_associated #0: 8 / 0.136 -> district non métropolitain
    n1=South Staffordshire | n2=district non métropolitain | rel=r_associated | relid=0 | w=8
  5. South Staffordshire -- r_associated #0: 5 / 0.085 -> circonscription britannique
    n1=South Staffordshire | n2=circonscription britannique | rel=r_associated | relid=0 | w=5
  6. South Staffordshire -- r_associated #0: 1 / 0.017 -> Angleterre
    n1=South Staffordshire | n2=Angleterre | rel=r_associated | relid=0 | w=1
  7. South Staffordshire -- r_associated #0: 1 / 0.017 -> comté
    n1=South Staffordshire | n2=comté | rel=r_associated | relid=0 | w=1
  8. South Staffordshire -- r_associated #0: 1 / 0.017 -> district
    n1=South Staffordshire | n2=district | rel=r_associated | relid=0 | w=1
  9. South Staffordshire -- r_associated #0: 1 / 0.017 -> District d'Angleterre
    n1=South Staffordshire | n2=District d'Angleterre | rel=r_associated | relid=0 | w=1
  10. South Staffordshire -- r_associated #0: 1 / 0.017 -> situé
    n1=South Staffordshire | n2=situé | rel=r_associated | relid=0 | w=1
  11. South Staffordshire -- r_associated #0: 1 / 0.017 -> staffordshire
    n1=South Staffordshire | n2=staffordshire | rel=r_associated | relid=0 | w=1
≈ 3 relations entrantes

  1. Staffordshire --- r_associated #0: 30 --> South Staffordshire
    n1=Staffordshire | n2=South Staffordshire | rel=r_associated | relid=0 | w=30
  2. South --- r_associated #0: 28 --> South Staffordshire
    n1=South | n2=South Staffordshire | rel=r_associated | relid=0 | w=28
  3. Midlands de l'Ouest --- r_associated #0: 20 --> South Staffordshire
    n1=Midlands de l'Ouest | n2=South Staffordshire | rel=r_associated | relid=0 | w=20
Le service Rézo permet d'énumérer les relations existant pour un terme. Ce service est interrogeable par programme.
Projet JeuxDeMots - url: http://www.jeuxdemots.org
contact: mathieu.lafourcade@lirmm.fr